Nuclear Physics and RadioactivityMedium
Question
The half - life of the radioactive radon is 3.8 days. The time , at the end of which 1 / 20th of the radon sample will remain undecided, is (given log10 e = 0.4343):
Options
A.3.8 day
B.16.5 day
C.33 day
D.76 day
Solution
M = M0e-γt 
= M0e-λt ⇒ ln 
= - λt
⇒
T1/2 = t ⇒ 
T1/2 = t
⇒ t = 16.42 days
= M0e-λt ⇒ ln = - λt⇒
T1/2 = t ⇒ T1/2 = t⇒ t = 16.42 days
Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
A radioactive sample disintegrates by 10% during one month. How much fraction will disintegrate in four months :-...The mass number of a nucleus is:...Initially only radioactive element A is present which is disintegrated into another stable element B. After 6hrs ratio o...zXM + 2He4 → 15P30 + 0n1...Assuming that 200 MeV of energy is released per fission of 92U235 atom. Find the number of fission per second required t...