HyperbolaHard
Question
AB is a double ordinate of the hyperbola 
= 1 such that ᐃAOB (where ′O′ is the origin) is an equilateral triangle, then the eccentricity e of the hyperbola satisfies -
= 1 such that ᐃAOB (where ′O′ is the origin) is an equilateral triangle, then the eccentricity e of the hyperbola satisfies -Options
A.e > √3
B.1 < e < 
C.e =
D.e >
Solution
Let l be the length of double ordinate.
Co-ordinate of point A is
so.
= 1⇒
= 1 ⇒ 
⇒
⇒ e2 - 1 > 
⇒ e2 > 
Create a free account to view solution
View Solution FreeMore Hyperbola Questions
The vertices of a hyperbola are at (0, 0) and (10, 0) and one of its foci is at (18, 0). The equation of the hyperbola i...The equation of hyperbola with vertices (-6,0) and (6,0) and semi latus rectum , is given by -...A point moves in a plane so that its distances PA and PB from two fixed points A and B in the plane satisfy the relation...A hyperbola has axes along coordinate axes. Its transverse axis is 2a and it passes through (h,k) then its eccentricity ...If the length of the transverse and conjugate axes of a hyperbola be 8 and 6 respectively, then the difference of focal ...