HyperbolaHard

Question

The equation of hyperbola with vertices (-6,0) and (6,0) and semi latus rectum , is given by -

Options

A.64x2 - 36y2 = - 2304
B.36x2 - 64y2 = - 2304
C.64x2 - 36y2 = 2304
D.36x2 - 64y2 = 2304

Solution

a = 6; ⇒ b2 = 64 ⇒ b = 8
∴ = 1

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