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Hyperbola
Hard
Question
The equation of hyperbola with vertices (-6,0) and (6,0) and semi latus rectum
, is given by -
Options
A.
64x
2
- 36y
2
= - 2304
B.
36x
2
- 64y
2
= - 2304
C.
64x
2
- 36y
2
= 2304
D.
36x
2
- 64y
2
= 2304
Solution
a = 6;
⇒ b
2
= 64 ⇒ b = 8
∴
= 1
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