HyperbolaHard
Question
The equation of hyperbola with vertices (-6,0) and (6,0) and semi latus rectum 
, is given by -
, is given by -Options
A.64x2 - 36y2 = - 2304
B.36x2 - 64y2 = - 2304
C.64x2 - 36y2 = 2304
D.36x2 - 64y2 = 2304
⇒ b2 = 64 ⇒ b = 8
= 1More Hyperbola Questions
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