HyperbolaMedium
Question
The equation of hyperbola with vertices (-6,0) and (6,0) and semi latus rectum 
, is given by -
, is given by -Options
A.64x2 - 36y2 = - 2304
B.36x2 - 64y2 = - 2304
C.64x2 - 36y2 = 2304
D.36x2 - 64y2 = 2304
⇒ b2 = 64 ⇒ b = 8
= 1More Hyperbola Questions
The equation 9x2 - 16y2 - 18x + 32y - 151 = 0 represent a hyperbola...The eccentricity of the hyperbola 4x2 - 9y2 - 8x = 32 is -...If PQ and PR are tangents drawn from a point P to the hyperbola = 1. If equation of QR is 4x − 3y − 6 = 0, t...If x = 9 is the chord of contact of the hyperbola x2 - y2 = 9, then the equation of the corresponding pair of tangents i...Let P be a point on the hyperbola x2 − y2 = a2 where a is a parameter such that P is nearest to the line y = 2x. T...