EllipseMedium
Question
An ellipse having foci at (3, 3) and (-4, 4) and passing through the origin has eccentricity equal to -
Options
A.3/7
B.2/7
C.5/7
D.3/7
Solution

Here S is (3, 3) & S’ is (-4, 4).
⇒ SS′ =
Now OS + OS′ = 2a
3√2 + 4 √2 = 2a
7√2 = 2a ... (ii)
From (i) & (ii)
e = 5/7
Create a free account to view solution
View Solution FreeMore Ellipse Questions
Let each of the two ellipses $E_{1}:\frac{x^{2}}{a^{2}} + \frac{y^{2}}{{\text{ }b}^{2}} = 1,(a > b)$ and $E_{2}:\frac...Find the equation of the tangent to the ellipse x2 + 2y2 = 4 at the points where ordinate is 1....Area of the greatest rectangle that can be inscribed in the ellipse = 1 is...If P is a point on the ellipse of eccentricity e and A, A′ are the vertices and S, S′ are the focii then ...The number of real tangents that can be drawn to the ellipse 3x2 + 5y2 = 32 and 25x2 + 9y2 = 450 passing through (3 , 5)...