EllipseHard

Question

An ellipse having foci at (3, 3) and (-4, 4) and passing through the origin has eccentricity equal to -

Options

A.3/7
B.2/7
C.5/7
D.3/7

Solution

     
Here S is (3, 3) & S’ is (-4, 4).
⇒    SS′ = = 2ae    .. (i)
Now OS + OS′ = 2a
3√2 + 4 √2 = 2a
7√2 = 2a    ... (ii)
From (i) & (ii)
e = 5/7

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