EllipseHard
Question
An ellipse having foci at (3, 3) and (-4, 4) and passing through the origin has eccentricity equal to -
Options
A.3/7
B.2/7
C.5/7
D.3/7
Solution
Here S is (3, 3) & S’ is (-4, 4).
⇒ SS′ =
= 2ae .. (i)Now OS + OS′ = 2a
3√2 + 4 √2 = 2a
7√2 = 2a ... (ii)
From (i) & (ii)
e = 5/7
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