Wave OpticsHard
Question
A monochromatic light source of wavelength λ is placed at S. Three slits S1, S2 and S3 are equidistant from the source S and the point P on the screen. S1P - S2P = λ /6 and S3P = 2λ /3. If I be the intensity at P when only one slit is open , the intensity at P when all the three slit are open is -
Options
A.31
B.51
C.81
D.zero
Solution
d12 = 
× 2 = 
d23 =
× 2 = 2π
A′ =
= √3A
⇒ I ∝ A2 ⇒ AR2 = 3A2 ⇒ IR = 3I
× 2 = d23 =
× 2 = 2πA′ =
= √3A⇒ I ∝ A2 ⇒ AR2 = 3A2 ⇒ IR = 3I
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