Wave OpticsHard

Question

Light of wavelength 6000 is reflected at nearly normal incidence from a soap films of refractive index 1.4. The least thickness of the film that will appear black is :

Options

A.infinity
B.200
C.2000
D.1000

Solution

            Soap film
Interference pccure occure between two reflected rays A and B is reflected from upper surface and B is reflected from lower surface.
The path difference between the two becomes 2μt +
If it is equal to then destructive interference ocdcurs and we see dark fringes fromabove. So the equation 2μt + = give the least value of t for which we see dark fringes.
2μt = λ ⇒ t = ≅ 2000

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