Wave OpticsHard
Question
The path difference between two interfering waves at a point on the screen is λ / 6. The ratio of intensity at this point and that at the central bright fringe will be : (Assume that intensity due to each slit is same )
Options
A.0.853
B.8.53
C.0.75
D.7.5
Solution
Path difference = 
∴ Phase difference =
∴ I = I1 + I2 + 2√I1√I2 cos
If I1 = I2 = I them intensity at central
I0 = I + I + 2√I√I cos 0o = 4I
and intensity at s point ′P′
I′ = I + I + 2√I × √I cos
= 3I =
× 4I = 
× I0 = 0.75 I0
∴ Phase difference =
∴ I = I1 + I2 + 2√I1√I2 cos
If I1 = I2 = I them intensity at central
I0 = I + I + 2√I√I cos 0o = 4I
and intensity at s point ′P′
I′ = I + I + 2√I × √I cos
= 3I =
× 4I = × I0 = 0.75 I0Create a free account to view solution
View Solution FreeMore Wave Optics Questions
A ray of light is incident on the surface of plate of glass of refractive index 1.5 at the polarising angle. The angle o...The figure shows the interference pattern obtained in double-slit experiment using light of wavelength 600 nm. P, Q, R, ...Ratio of intensity of two waves is 25 : 1. If interference occurs, then ratio of maximum and minimum intensity should be...In a diffraction pattern due to a single slit of width ‘a’, the first minimum is observed at an angle 30o wh...In Young double slit experiment if distance between sources is made double then central fringe width will be :-...