Wave OpticsHard
Question
The path difference between two interfering waves at a point on the screen is λ / 6. The ratio of intensity at this point and that at the central bright fringe will be : (Assume that intensity due to each slit is same )
Options
A.0.853
B.8.53
C.0.75
D.7.5
Solution
Path difference = 
∴ Phase difference =
∴ I = I1 + I2 + 2√I1√I2 cos
If I1 = I2 = I them intensity at central
I0 = I + I + 2√I√I cos 0o = 4I
and intensity at s point ′P′
I′ = I + I + 2√I × √I cos
= 3I =
× 4I = 
× I0 = 0.75 I0
∴ Phase difference =
∴ I = I1 + I2 + 2√I1√I2 cos
If I1 = I2 = I them intensity at central
I0 = I + I + 2√I√I cos 0o = 4I
and intensity at s point ′P′
I′ = I + I + 2√I × √I cos
= 3I =
× 4I = × I0 = 0.75 I0Create a free account to view solution
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