Wave OpticsHard
Question
In an interference arrangement similar to Young’s double - slit experiment, the slits S1 and S2 are illuminated with coherent microwave source, each of frequency 106 Hz. The source are synchronized to have zero phase difference. The slits are separated by a distance d = 150.0m The intensity I(θ) is measured as a function of θ, where θ is defined as shown, If I0 is the maximum intensity, then I(θ) for 0 ≤ θ ≤ 90o is given by :
Options
A.I(θ) = I0 / 2 for θ = 30o
B.I(θ) = I0 / 4 for θ = 90o
C.I(θ) = I0 for θ = 0o
D. I(θ) is constant for all values of θ
Solution
The intensity of light is (θ) = I0 cos2
Where δ =
(ᐃx) = 
(d sin θ)
(i) For θ = 30o
λ =
= 300 m and d = 150 m
δ =
(150) 
∴ 
∴I(θ) = I0 cos2
(ii) For θ = 90o
δ =
(150) (1) = π ⇒ 
and I(θ)
(iii) For θ = 0o : δ = 0 ⇒
= 0 ∴I(θ) = I0
Where δ =
(ᐃx) = (d sin θ)(i) For θ = 30o
λ =
= 300 m and d = 150 mδ =
(150) ∴ ∴I(θ) = I0 cos2
(ii) For θ = 90o
δ =
(150) (1) = π ⇒ and I(θ)(iii) For θ = 0o : δ = 0 ⇒
= 0 ∴I(θ) = I0Create a free account to view solution
View Solution FreeMore Wave Optics Questions
In diffraction experiment, intensity at centre of screen in case of circular disc will be :-...A light source of 5000 wave length produces a single slit diffraction. The first minima in diffraction pattern is seen, ...Interference occurs in which of the following waves?...The waves of 600μ m wave length are incident normally on a slit of 1.2mm width. The value of diffraction angle corr...If an interference pattern have maximum and minimum intensities in 36 :1 ratio then what will be the ratio of amplitudes...