Geometrical OpticsMedium
Question
y =
sin πx ; 
cos π x π ⇒ 
= ± 1an 45o = 1 = 2 cosπx
cos πx =
⇒ π x = 
∴ x = 
and 
∴ y =
In the fig. shown consider the first reflection at the plane mirror and second at the convex mirror. AB is object. 
Options
A.the second image is real and inverted with magnification 1/5
B.the second image is virtual and inverted with magnification 1/5
C.the second image moves towards the convex mirror
D.the second image moves away from the convex mirror
Solution
u1 = - 60 & u2 = - 90
-
⇒ v1 = 30
⇒ v2 = 36v2 - v1 = 36 - 30 = 6 cm
m =
for mirror v1 = - m2v0
convex mirror makes virtual image.
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