Geometrical OpticsHard
Question
y =
sin πx ; 
cos π x π ⇒ 
= ± 1an 45o = 1 = 2 cosπx
cos πx =
⇒ π x = 
∴ x = 
and 
∴ y =
In the fig. shown consider the first reflection at the plane mirror and second at the convex mirror. AB is object. 
Options
A.the second image is real and inverted with magnification 1/5
B.the second image is virtual and inverted with magnification 1/5
C.the second image moves towards the convex mirror
D.the second image moves away from the convex mirror
Solution
u1 = - 60 & u2 = - 90
-
⇒ v1 = 30
⇒ v2 = 36v2 - v1 = 36 - 30 = 6 cm
m =
for mirror v1 = - m2v0
convex mirror makes virtual image.
Create a free account to view solution
View Solution FreeMore Geometrical Optics Questions
A rod of length 10 cm lies along the principal axis of a concave mirror of focal length 10 cm in sucha way that its end ...Monochromatic light is refracted from air into the glass of refractive index m. The ratio of the wavelength of incident ...Spherical aberration in a thin lense can be reduced by...Wavelength of green light is 5460 is incident at air-glass surface, if refractive index of glass is 1.5 then value of wa...Two lenses in contact made of materials with dispersive powers in the ratio 2 : 1, behaves as an achromatic diverging fo...