Geometrical OpticsMedium
Question
In a microscope of tube length 10 cm two convex lenses are arranged with focal length of 2 cm and 5 cm . Total magnification obtained with this system for normal adjustment is $(5)^{k}$. The value of k is $\_\_\_\_$
Options
A.2
B.5
C.3.5
D.4
Solution
$f_{0} = 2\text{ }cm,fe = 5\text{ }cm$
$${\mathcal{l} = 10\text{ }cm,D = 25\text{ }cm }{M = \frac{\mathcal{l}}{f_{0}} \cdot \frac{D}{f_{e}} = 25}$$
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