Geometrical OpticsMedium
Question
A cubical block of glass of refractive index n1 is in contact with the surface of water refractive index n2. A beam of light is incident on vertical face of the block and refraction at the opposite vertical face, the ray emerges out at an angle θ. The value θ is given by -
Options
A.sin θ < 
B.tan θ <
C.sin θ <
D.tan θ <
Solution
n1sin θC = n2 ⇒ sin θC =
1 × sin θ = n1 sin (90 - θC) = n1cos θC = n1
θ = sin-1
; sin < 
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