Geometrical OpticsMedium
Question
A .point source S is placed at the bottom of different layers as shown in the figure. The refractive index of bottommost layer is μ0. The refractive index of any other upper layer is μ(n) = μ0 +
A ray of light with angle i = 30o starts from the source S. Total internal reflection takes place at the upper surface of layer having n equal to .


Options
A.3
B.5
C.4
D.6
Solution
For parallel composite slab u sinθ = constant
μ0 × sin i = μ (n) × sin 90o
μ0 sin 30o = μ0 +
= 1 +
⇒ n= 4
⇒ upper layer of n = 3
μ0 × sin i = μ (n) × sin 90o
μ0 sin 30o = μ0 +
⇒ upper layer of n = 3
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