KinematicsHard
Question
A particle of mass m moves along a curve y = x2. When particle has x-co-ordinate as 1/2 and x - component of velocity as 4 m/s. Then : -
Options
A.The position coordinate of particle are (1/2, 1/4)
B.The velocity of particle will be along the line 4x - 4y - 1 = 0
C.The magnitude of velocity at the that instant is 4
m/s
m/sD.The magnitude of angular moment of particle about origin at the position is 0.
Solution
y = x2, 
= 
= 2x 
= 2x vx
vy = 2 ×
× 4 (at x = 
, vx = 4)
vy = 4m/s ;
= 4î + 4ĵ ; |
| = 4
Slope of line 4x - 4y - 1 = 0 is tan 45o = 1 and also the slope velocity is 1.
= = 2x = 2x vxvy = 2 ×
× 4 (at x = , vx = 4)vy = 4m/s ;
= 4î + 4ĵ ; || = 4Slope of line 4x - 4y - 1 = 0 is tan 45o = 1 and also the slope velocity is 1.
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