KinematicsHard
Question
A particle moves along the X-axis as x = u(t - 2s) + a(t - 2s)2 : -
Options
A.The initial velocity of the particle is u
B.The acceleration of the particle is a
C.The initial velocity of the particle is u
D.At t = 2s particle is at the origin.
Solution
x = u (t - 2) + a (t - 2)2 ...(i)
v =
= u + 2a(t - 2)
Therefore v(0) = u - 4a
a =
= 2a. Hence [C]
x(2) = 0 [From (i)] Hence [D]
v =
= u + 2a(t - 2)Therefore v(0) = u - 4a
a =
= 2a. Hence [C]x(2) = 0 [From (i)] Hence [D]
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