KinematicsHard
Question
The total speed of a projectile at its greatest is 
of its speed when it is half of its greatest height. The angle of projection will be : -
of its speed when it is half of its greatest height. The angle of projection will be : -Options
A.60o
B.45o
C.30o
D.50o
Solution
vy2 = u2 sin2 θ = 2g ×
; vx2 = u2 cos2θ∴ u cos θ =
⇒ cos θ = 
or θ = 30oCreate a free account to view solution
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