AIPMT | 2015KinematicsEasy
Question
A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to
v(x) = βx-2n
where β and n are constants and x is the position of the particle. The acceleraion of the particle as a function of x, is given by :
v(x) = βx-2n
where β and n are constants and x is the position of the particle. The acceleraion of the particle as a function of x, is given by :
Options
A.-2nβ2x-4n-1
B.-2nβ2x-2n+1
C.-2nβ2e-4n+1
D.-2nβ2x-2n-1
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