Application of DerivativeHard
Question
If x = t2 and y = 2t, then equation of normal at t = 1 is-
Options
A.x + y + 3 = 0
B.x + y + 1 = 0
C.x + y - 1 = 0
D.x + y - 3 = 0
Solution
x = t2, y = 2t at t = 1 normal
= 2t 
= 2
= - t = -1
equation of normal y - 2 = -1 (x - 1)
x + y = 3
x + y - 3 = 0
= 2t = 2= - t = -1equation of normal y - 2 = -1 (x - 1)
x + y = 3
x + y - 3 = 0
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