Application of DerivativeHard
Question
The equation of normal to the curve y2 = 16x at the point (1, 4) is-
Options
A.2x + y = 6
B.2x - y + 2 = 0
C.x + 2y = 9
D.None of these
Solution
y2 = 16x
2y
= 16
slope of tangent at (1, 4) is 2
slope is normal is = -
eq of normal at (1, 4) is
y - 4 = -
(x - 1)
⇒ x + 2y = 9
2y
= 16slope of tangent at (1, 4) is 2
slope is normal is = -
eq of normal at (1, 4) is
y - 4 = -
(x - 1)⇒ x + 2y = 9
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