Application of DerivativeMedium
Question
The points on the curve 9y2 = x3 where the normal to the curve makes equal intercepts with coordinates axes is-
Options
A.
B.
C.
D.None of these
Solution
Let the point on the curve 9y2 = x3 is P(x1, y1)
2 × 9 × y ×
= 3x2
Normal of slope = -
so
= ± 1
= 1
-3y1 × 2 = x21 so 9 ×
= x31
so
= - 1
2 × 3y1 = x21 .... (i)
also lies point on the curve 9y2 = x3
9 y21 = x31
9 ×
= x31
x1 = 4
x1 = 4, y1 =
finally point are
or 
2 × 9 × y ×
= 3x2Normal of slope = -
so
= ± 1 = 1-3y1 × 2 = x21 so 9 ×
= x31so
= - 12 × 3y1 = x21 .... (i)
also lies point on the curve 9y2 = x3
9 y21 = x31
9 ×
= x31 x1 = 4
x1 = 4, y1 =
finally point are
or Create a free account to view solution
View Solution FreeMore Application of Derivative Questions
At what point the slope of the tangent to the curve x2 + y2 − 2x − 3 = 0 is zero-...If the tangent at any point on the curve x4 + y4 = a4 cuts off intercept p and q on the axes, the value of p-4/3 + q-4/3...The angle of intersection between the curves y2 = 8x and x2 = 4y − 12 at (2, 4) is -...The radius of a spherical soap bubble is increasing at the rate of 0.2 cm/sec, then the rate of increase of its surface ...If tn be the nth term of the series 1 + 3 + 7 + 15 + ......... then -...