Application of DerivativeMedium
Question
The equation of the normal to the curve y2 = 4ax at point (a, 2a) is-
Options
A.x - y + a = 0
B.x + y - 3a = 0
C.x + 2y + 4a = 0
D.x + y + 4a = 0
Solution
y2 = 4ax at (a, 2a)
2y
= 4a
∴ Slope of normal is - 1
y - 2a = -1 (x - a)
x + y = 3a
2y
= 4a∴ Slope of normal is - 1
y - 2a = -1 (x - a)
x + y = 3a
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