Application of DerivativeHard
Question
The equation of the normal to the curve y2 = 4ax at point (a, 2a) is-
Options
A.x - y + a = 0
B.x + y - 3a = 0
C.x + 2y + 4a = 0
D.x + y + 4a = 0
Solution
y2 = 4ax at (a, 2a)
2y
= 4a
∴ Slope of normal is - 1
y - 2a = -1 (x - a)
x + y = 3a
2y
= 4a∴ Slope of normal is - 1
y - 2a = -1 (x - a)
x + y = 3a
Create a free account to view solution
View Solution FreeMore Application of Derivative Questions
The curve y - exy + x = 0 has a vertical tangent at...Consider the curve f(x) = x1/3, then -...If equation of normal at a point (m2, -m3) on the curve x3 - y2 = 0 is y = 3mx - 4m3, then m2 equals-...The angle of intersection between the curves y2 = 16x and 2x2 + y2 = 4 is-...If the line ax + by + c = 0 is a normal to the curve xy = 1, then-...