CircleHard
Question
The equation of the circle passing through the foci of the ellipse 
and having centre at (0, 3) is :
and having centre at (0, 3) is : Options
A. x2 + y2 - 6y - 7 = 0
B. x2 + y2 - 6y + 7 = 0
C. x2 + y2 - 6y - 5 = 0
D. x2 + y2 - 6y + 5 = 0
Solution
foci
centre of circle is (0, 3)
x2 + y2 - 6y + c = 0
passes through (√7, 0)
7 + 0 - 0 + c = 0
c = -7
So x2 + y2 - 6y - 7 = 0
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