CircleHard

Question

The equation of the circle passing through the foci of the ellipse and having centre at (0, 3) is :

Options

A. x2 + y2 - 6y - 7 = 0
B. x2 + y2 - 6y + 7 = 0
C. x2 + y2 - 6y - 5 = 0
D. x2 + y2 - 6y + 5 = 0

Solution



foci
centre of circle is (0, 3)
x2 + y2 - 6y + c = 0
passes through (√7, 0)
7 + 0 - 0 + c = 0
c = -7
So x2 + y2 - 6y - 7 = 0

Create a free account to view solution

View Solution Free
Topic: Circle·Practice all Circle questions

More Circle Questions

The common tangents to the circle x2 + y2 = 2 and the parabola y2 = 8x touch the circle at the points P, Q and the parab...An equilateral triangle OAB is inscribed in the parabola $y^{2} = 4x$ with the vertex O at the vertex of the parabola. T...The number of tangents that can be drawn from the point (8, 6) to the circle x2 + y2 _ 100 = 0 is...The locus of the center of a circle which touches externally the circle, x2 + y2 - 6x - 6y + 14 = 0 and also touches the...Equation x2 - 2x - 2y + 5 = 0 represents -...