CircleMedium
Question
The locus of the center of a circle which touches externally the circle, x2 + y2 - 6x - 6y + 14 = 0 and also touches the y-axis is given by the equation -
Options
A.x2 - 6x - 10y + 14 = 0
B.x2 - 10x - 6y + 14 = 0
C.y2 - 6x - 10y + 14 = 0
D.y2 - 10x - 6y + 14 = 0
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