Application of DerivativeHard
Question
The equation of tangent to the curve y = 2sinx + sin2x at the point x = π/3 is-
Options
A.2y = √3
B.3y = √2
C.2y = 3 √3
D.2y = 3
Solution
y = 2sinx + sin2x at point x = π/3
= 2 cosx + 2cos2x
= 2 × 
+ 2 × 
= 1 - 1 = 0
x = π/3 ; y = 2 ×
y =
× 3
point
= 0
y =
= 2 cosx + 2cos2x= 2 × + 2 × = 1 - 1 = 0x = π/3 ; y = 2 ×
y =
× 3point
= 0y =
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