Application of DerivativeHard
Question
The radius of a sphere is changing at the rate of 0. 1 cm/sec. The rate of change of its surface area when the radius is 200 cm, is-
Options
A.8π cm2/sec
B.12π cm2/sec
C.160p cm2/sec
D.200π cm2/sec
Solution
A = 4πr2
⇒
= 8πr
⇒
= 8π × 200 × 0. 1
[∵ r = 200 &
= 0. 1]
⇒
= 160π cm2/sec
⇒
= 8πr⇒
= 8π × 200 × 0. 1[∵ r = 200 &
= 0. 1]⇒
= 160π cm2/secCreate a free account to view solution
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