Application of DerivativeMedium
Question
The equation of the normal to the curve y2 = x3 at the point whose abscissa is 8, is-
Options
A.x ± √2 y = 104
B.x ± 3√2 y = 104
C.3√2 x ± y = 104
D.None of these
Solution
The equation of the normal
y2 = x3 at x = 8
y2 = 29
y = ± 24 √2
y = ± 16 √2
y2 = x3 point (8, ± 16 √2)
2y ×
= 3x2
= ± 3√2
= 
(y
16 √2) = 
(x - 8)
3√2 y ± 96 = (x - 8)
y2 = x3 at x = 8
y2 = 29
y = ± 24 √2
y = ± 16 √2
y2 = x3 point (8, ± 16 √2)
2y ×
= 3x2= ± 3√2 = (y
16 √2) = (x - 8) 3√2 y ± 96 = (x - 8)Create a free account to view solution
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