Continuity and DifferentiabilityHard
Question
Let f(x) = a + b | x | + c | x |4, where a, b and c are real constants. Then f(x) is differentiable at x = 0, if -
Options
A.a = 0
B.b = 0
C.c = 0
D.None of these
Solution
f(x) = a + b | x | + c | x |4
f(x) =
f′(x) =
diff. at x = 0 when b = 0
f(x) =
f′(x) =
diff. at x = 0 when b = 0
Create a free account to view solution
View Solution FreeMore Continuity and Differentiability Questions
If y = ln(cosecx - cotx), then equals -...If y = sec , then dy/dx equals-...If x = a (cos θ + qsin θ), y = a (sin θ − θ cos θ) then at θ = π equals to -...If f′(c) exists and non-zero then is equal to -...If f(x) = [x], where [x] = greatest integer ≤ x, then at x = 1, f is-...