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Continuity and Differentiability
Hard
Question
If f(x) = | x - 1| and g(x) = f[f{f(x)}] then for x > 2, g′(x) is equal to-
Options
A.
-1, if 2 ≤ x < 3
B.
1, if 2 ≤ x < 3
C.
1, for all x > 2
D.
None of these
Solution
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