Continuity and DifferentiabilityMedium
Question
If y = sin (m sin-1x), then (1 - x2) y″ -xy′ is equal to -
Options
A.m2y
B.my
C.-m2y
D.None of these
Solution
y = sin (m sin-1 x)
y′ = m cos(m sin-1 x) ×
y =
(1 - x2) y″ = -m2y + x.y′
(1 - x2) y″ = xy′ = -m2y
y′ = m cos(m sin-1 x) ×
y =
(1 - x2) y″ = -m2y + x.y′
(1 - x2) y″ = xy′ = -m2y
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