Continuity and DifferentiabilityHard

Question

If xe^xy - y = sin x, then at x = 0 is-

Options

A.0

B.1

C.-1

D.None of these

Solution

x e^xy - y = sin x
e^xy _{+ x.e} ^xy {y + x. } - = cos x
at x = 0, y = 0
∴ at x (0, 0) is
e⁰ + 0.e⁰ {0 + 0} - = cos 0
= 0

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