Continuity and DifferentiabilityHard
Question
If xexy - y = sin x, then 
at x = 0 is-
at x = 0 is-Options
A.0
B.1
C.-1
D.None of these
Solution
x exy - y = sin x
exy + x.e xy {y + x.
} - 
= cos x
at x = 0, y = 0
∴
at x (0, 0) is
e0 + 0.e0 {0 + 0} -
= cos 0
= 0
exy + x.e xy {y + x.
} - = cos xat x = 0, y = 0
∴
at x (0, 0) ise0 + 0.e0 {0 + 0} -
= cos 0= 0Create a free account to view solution
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