Alternating CurrentHard
Question
A coil has resistance 30Ω and inductive resistance 20Ω at 50 Hz frequency. If an ac source, of 200 volt, 100 Hz, is connected across the coil, the current in the coil will be
Options
A.2.0 A
B.4.0 A
C.8.0 A
D.
Solution
Here, Resistance, R = 30Ω
Inductive resistance, XL = 20Ω at 50 Hz
∴ XL = 2π
L
∴
× 20 Ω = 40 Ω
Impedence, Z =
Current in the coil, I =
Inductive resistance, XL = 20Ω at 50 Hz
∴ XL = 2π
L∴
× 20 Ω = 40 Ω Impedence, Z =
Current in the coil, I =
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