Trigonometric EquationHard
Question
If 0 ≤ α, β ≤ 90o and tan (α + β) = 3 and tan (α - β) = 2, then value of sin 2 α is -
Options
A.
B.
C.
D.None of these
Solution
If 0 ≤ α, β ≤ 90o and tan (α + β) = 3 and
an(α - β) = 2, then the value of sin2α is
tan2α = tan[(α + β) + (α - β)]
=
= -1
0 < α, β < 90o ⇒ 0 < 2α < 180o ⇒ 2a = 135o
sin2α = sin 135o =
an(α - β) = 2, then the value of sin2α is
tan2α = tan[(α + β) + (α - β)]
=
= -10 < α, β < 90o ⇒ 0 < 2α < 180o ⇒ 2a = 135o
sin2α = sin 135o =
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