Trigonometric EquationHard
Question
Distance between the planes 
= 3 & 2x + 4y = 4z + 5 is equal to -
= 3 & 2x + 4y = 4z + 5 is equal to -Options
A.1/4
B.1/2
C.1/3
D.1/6
Solution
p1 = 
= 3
⇒ x + 2y – 2z = 3 ........(i)
P2 : 2x + 2y – 4z = 5
⇒ x + 2y - 2z = 5/2 ........(ii)
Distance between (i) & (ii) is equal to
= 3⇒ x + 2y – 2z = 3 ........(i)
P2 : 2x + 2y – 4z = 5
⇒ x + 2y - 2z = 5/2 ........(ii)
Distance between (i) & (ii) is equal to
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