Trigonometric EquationHard
Question
Let n be a positive integer such that sin 
+ cos 
= 
. Then :
+ cos = . Then :Options
A.n = 6
B.n = 1, 2, 3, .......,8
C.n = 5
D.None of these
Solution
Given sin 
+ cos 
= 
squaring at both the side
sin2
+ cos2 
+ 2sin 
cos 
=
1 + sin
1 + sin
sin
- 1 ⇒ 
n = 6 only
+ cos = squaring at both the side
sin2
+ cos2 + 2sin cos =1 + sin
1 + sin
sin
- 1 ⇒ n = 6 only Create a free account to view solution
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