Solution of differential equation (1 + y2)dx + (x - etan-1y)dy = 0 is -

(1 + y2) + x = etan-1yI.F. = etan-1yXetan-1y = dy⇒ Xetan-1y = e2tan-1y + c

Differential EquationHard

Question

Solution of differential equation (1 + y²)dx + (x - e^{tan^-1y})dy = 0 is -

A.ye^{tan^-1x} = tan^-1 x + c

B.xe^{tan^-1y} = e^{2tan^-1} + c

C.2x = e^{tan^-1y} + c

D.y = xe^{-tan^-1x} + c

(1 + y²) + x = e^{tan^-1}y

I.F. = e^{tan^-1}y
Xe^{tan^-1y} = dy
⇒ Xe^{tan^-1y} = e^{2tan^-1y} + c

Create a free account to view solution