Redox and Equivalent ConceptHard

Question

0.116 g of C4H4O4 (A) is neutralised by 0.074 g of Ca(OH)2. Hence protonic hydrogen (H+) in (A) will be

Options

A.1
B.2
C.3
D.4

Solution

(0.116/116)×n-factor = (0.074/74)×2
⇒ n-factor = 2

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