Heat and Thermal ExpansionHard

Question

5g of steam at 100oC is mixed at 100oC is mixed with 10g of ice at 0oC. Chose correct alternative/s) :- (Given swater = 1 cal / goC, LF = 80 cal / g, LV = 540 cal / g)

Options

A.Equilibrium ,temperature  of mixture is is 160oC
B.Equilibrium ,temperature  of mixture is is 100oC
C.At equilibrium, mixture contain 13 g of water
D.At equilibrium, mixture contain 1 g of steam

Solution

Required heat              Available heat
10 g ice (0oC)             5 g steam (100oC)
↓800 cal                        ↓   2700 cal
10 g water (0oC)         5 g water (100oC)    
↓1000 cal
10 g water (100o)
So available heat is more than required heat therefore final temperature will be 100oC.
Mass of vapour condensed
= g
Total mass of water
= 10 + = 13 g
Total mass of steam
= 5 - g

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