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Question
Which of the following solution will have pH = 13 ?
Options
A.2g NaOH in 500 mL solution.
B.100 mL solution of 0.05 M Ca(OH)2.
C.100 mL solution 0.1 N Ca(OH)2.
D.4g NaOH in 500 mL solution.
Solution
a M = 
= 0.1 M
∴ [NaOH] = [OH-] = 0.1 = 10-1 M
pOH = 1, pH = 13
b. 0.05 M Ca(OH)2 = 2 × 0.05 N Ca(OH)2
∴ [OH-] = 2 × 0.05 = 0.1 = 10-1 M
pOH = 1 pH = 13
c. 100 mL of 0.1 N Ca(OH)2,
∴ [OH-] = 0.1 N = 10-1 M
pOH = 1 pH = 13
d. M =
= 0.1 M
[OH-] = 0.2 M
pOH = -log[0.2] = -log 2 + log 10 = -0.3010 + 1 = 0.699
pH = 14 - 0.699 = 13.301
So the answer (a), (b) and (c) are correct.
= 0.1 M∴ [NaOH] = [OH-] = 0.1 = 10-1 M
pOH = 1, pH = 13
b. 0.05 M Ca(OH)2 = 2 × 0.05 N Ca(OH)2
∴ [OH-] = 2 × 0.05 = 0.1 = 10-1 M
pOH = 1 pH = 13
c. 100 mL of 0.1 N Ca(OH)2,
∴ [OH-] = 0.1 N = 10-1 M
pOH = 1 pH = 13
d. M =
= 0.1 M[OH-] = 0.2 M
pOH = -log[0.2] = -log 2 + log 10 = -0.3010 + 1 = 0.699
pH = 14 - 0.699 = 13.301
So the answer (a), (b) and (c) are correct.
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