KTGMedium
Question
The specific heats of a gas are CP = 0.2 cal / g oC & CV = 0.15 cal / g oC .[Take R = 2 cal / mol oC]
Options
A.The molar mass of the mass of the gas is 40g
B.The molar mass of the gas cannot be determined from the data given
C.The number of degree of freedom of the gas molecules is 6
D.The number of degree of freedom of the gas molecules is 8
Solution
CP - CV = R; M (0.20 - 0.15) = 2 [M = molar mass]
⇒ M =
= 40g
⇒ f = degrees of freedom = 6
⇒ M =
= 40g⇒ f = degrees of freedom = 6
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