Heat and Thermal ExpansionHard
Question
An ideal gas can be expended from an initial state to a certain volume through two different processes
(i) PV2 = constant and (ii) P = KV2 where K is a positive constant. Then :-
(i) PV2 = constant and (ii) P = KV2 where K is a positive constant. Then :-
Options
A.Final temperature in (i) will be greater than in (ii)
B.Final temperature in (ii) will be greater than in (i)
C.Total heat given to the gas in case is greater than in (ii)
D.Total heat given to the gas in (i) case is greater than in (i)
Solution
(i) PV2 = C ⇒ TV = C
If volume expands temperature decrease.
(ii) P = KV2 ⇒
= constant
If volume expands, temprature increase

Q = ᐃU + W
Q2 > Q as W2 W2 > ᐃU2 > ᐃU1
If volume expands temperature decrease.
(ii) P = KV2 ⇒
If volume expands, temprature increase

Q = ᐃU + W
Q2 > Q as W2 W2 > ᐃU2 > ᐃU1
Create a free account to view solution
View Solution FreeMore Heat and Thermal Expansion Questions
An angular rod of same uniform material as shown in figure is conducting heat at a steady rate. The temperature gradient...A meter washer has a hole of diameter d1 and external d2, where d2 = 3d1. On heating, d2 increase by 0.3%. Then d1 will ...Density of water at $4^{\circ}C$ and $20^{\circ}C$ are $1000\text{ }kg/m^{3}$ and respectively. The increase in internal...Pressure versus temperature graph of an ideal gas is shown in figure. Density of the gas at point A is. ρ0 Density ...Hailstone at 0oC falls from a height of 1 km on an insulating surface converting whole of its kinetic energy into heat. ...