Chemical EquilibriumHard
Question
XY2 dissociates XY2(g) ⇋ XY(g) + Y(g). When the initial pressure of XY2 is 600 mm Hg, the total equilibrium pressure is 800 mm Hg. Calculate K for the reaction. Assuming that the volume of the system remains unchanged.
Options
A.50.0
B.100.0
C.166.6
D.400.0
Solution
XY2 ⇋ XY + Y
Initial P 0 0
Final P - x x x
Initial P = 600 mm Hg, Final P = 800 mm Hg
Total moles ∝ final P.
∴ P - x + x + x ∝ 800
600 - x + x + x ∝ 800
x = 200 mm Hg
K =
= 100 HG
Initial P 0 0
Final P - x x x
Initial P = 600 mm Hg, Final P = 800 mm Hg
Total moles ∝ final P.
∴ P - x + x + x ∝ 800
600 - x + x + x ∝ 800
x = 200 mm Hg
K =
= 100 HGCreate a free account to view solution
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