ThermodynamicsMedium
Question
The molar specific heat of the the process V ∝ T4 for CH4 at room temperature is : -
Options
A.4 R
B.7 R
C.3 R
D.8 R
Solution
V ∝ T4 ⇒ V ∝ (PV)4
⇒ P4V3 = contant ⇒ PV3/4 = constant
∴ C = Cv +
=3R + 4R = 7R
⇒ P4V3 = contant ⇒ PV3/4 = constant
∴ C = Cv +
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