Heat and Thermal ExpansionHard

Question

A steel scale is to be prepared such that the millimeter intervals are to be accurate4 within 6 × 10-5 mm.The maximum temperature variation during the ruling of the millimeter makes is (α = 12 × 10-6C-1) :-

Options

A.4.0oC
B.4.5oC
C.5.0oC
D.5.5oC

Solution

ᐃL = 6 × 10-5 = Lαθ ⇒ θ = = 5oC

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