Solid StateHard
Question
For the spinel structure (MgAl2O4), the correct statement is/are
Options
A.50% OVs are occupied by ions.
B.Al3+ is equally distributed in TVs and OVs.
C.Oxide ions occupy ccp lattice.
D.12.5% TVs are occupied by ions.
Solution
For spinel structure, O2- ions form fcc arrangement.
∴ Number of O2- ions = 4,
Number of TV = 8, Number of OV = 4
Number of Mg2+ ions =
× TV = 
× 8 = 1
Number of Al3+ ions =
× OV = 
× 4 = 2
So, 50% OVs are occupied and 1/8th, i.e., 12.5% TVs are occupied,
∴ Number of O2- ions = 4,
Number of TV = 8, Number of OV = 4
Number of Mg2+ ions =
× TV = × 8 = 1 Number of Al3+ ions =
× OV = × 4 = 2So, 50% OVs are occupied and 1/8th, i.e., 12.5% TVs are occupied,
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