Atomic StructureHard
Question
Assume that a neutron breaks into a proton andan electron. The energy released during thisprocess is :
(Mass of neutron = 1.6725 × 10-27 kg
Mass of proton = 1.6725 × 10-27 kg
Mass of electron = 9 × 10-31 kg)
(Mass of neutron = 1.6725 × 10-27 kg
Mass of proton = 1.6725 × 10-27 kg
Mass of electron = 9 × 10-31 kg)
Options
A.5.4 MeV
B.0.73 MeV
C.7.10 MeV
D.6.30 MeV
Solution
If mass of neutron = 1.6747 × 10-27 kg
then answer will be (2)
Released energy = [1.6747 × 10-27 - 1.6725 ×10-27 - 9 × 10-31] × (3 × 108)2 J = 0.73 MeVγ
then answer will be (2)
Released energy = [1.6747 × 10-27 - 1.6725 ×10-27 - 9 × 10-31] × (3 × 108)2 J = 0.73 MeVγ
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The operation of a nuclear reactor is said to be critical, if multiplication factor (K)has a value...When 5V potential difference is applied across a wire of length 0.1 m, the drift speed of electrons is 2.5 × 10-4 m...Radioactive nuclei that are injected into a potient collected at certain sites within its body, undergoing radioactive d...The de Broglie wavelength of an oxygen molecule at $27^{\circ}C$ is $x \times 10^{- 12}\text{ }m$. The value of x is (ta...Which of the following statements is correct?...