Geometrical OpticsHard
Question
A single slit Fraunhofer diffraction pattern is formed with white light. For what wavelength of light the third secondary maximum in the diffraction pattern coincides with the second secondary maximum in the pattern for red light of wavelength 6500 
: -
: - Options
A.4400
B.4100
C.4642.8
D.9100
Solution
x = 
For red light : x =
× 6500
For other light x =
× λ
x is same for each.
∴ 5 × 6500 = 7 × λ or λ =
× 6500 = 4642.8
For red light : x =
× 6500For other light x =
× λ x is same for each.
∴ 5 × 6500 = 7 × λ or λ =
× 6500 = 4642.8 Create a free account to view solution
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