Current Electricity and Electrical InstrumentHard
Question
A voltmeter connected in series with a resistance R1 to a circuit indicates a voltage V1 = 198 V. When a series resistor R2 = 2R1 is used, the voltmeter indicates a voltage V2 = 180 V. If the resistance of the voltmeter is RV = 900Ω then, the applied voltage across A and B is:-
Options
A.210 V
B.200 V
C.220 V
D.240 V
Solution
198 = 
........(i)
180 =
× 900 ........(ii)
divided Eq (i) by (ii)
and on solving it R1 = 100 Ω
Now put value of R1 in any one equation.
........(i)180 =
× 900 ........(ii)divided Eq (i) by (ii)
and on solving it R1 = 100 Ω
Now put value of R1 in any one equation.
Create a free account to view solution
View Solution FreeTopic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
A galvanometer of 100Ω resistance gives complete deflection on flowing 10 mA current. What should be the value of s...The current in a conductor varies with time t as I = 2t + 3t2 amp. where I is ampere and t in second. Electric charge fl...In the arrangement shown in figure when the switch S2 is open, the galvanometer chows no deflection for . When the switc...In an A.C. circuit, the current flowing in inductance is I= 5 sin (100t - π / 2)amperes and the potential different...A galvanometer coil has a resistance 90W and full scale deflection correct 10mA. A 910W resistance is connected in serie...