SHMHard
Question
One end of a spring of force constant k is fixed to a fixed vertical wall and the other to a block of mass m resting on a smooth horizontal surface. There is another wall at a distance x0 from the block. The spring is then compressed by 2x0 and released. The time taken to strike the wall is :-


Options
A.
B.
C.
D.
Solution

The total time from A to C
tAC = tAB + tBC = (T/4) + tBC
where T = time period of oscillation of spring mass system
tBC can be obtained from,
BC = AB sin(2π/T)tBC
Putting
⇒ tAC =
Create a free account to view solution
View Solution FreeMore SHM Questions
A spring of force constant a has two blocks of same mass M connected to each end of the spring as shown in figure. Same ...Two simple harmonic motions are represented by the equation y1 = 0.1 sin and y2 = 0.1 cosπt. The phase difference o...What would be the period of the free oscillations of the system shown here if mass M1 is pulled down a little force cons...A pendulum has time period T in air. When it is made to oscillate in water, it acquired a time period T′ = √...A solid cylinder of mass M attached to a mass less spring of force constant k is placed on a horizontal surface in such ...