SHMHard
Question
One end of a spring of force constant k is fixed to a fixed vertical wall and the other to a block of mass m resting on a smooth horizontal surface. There is another wall at a distance x0 from the block. The spring is then compressed by 2x0 and released. The time taken to strike the wall is :-
Options
A.
B.
C.
D.
Solution
The total time from A to C
tAC = tAB + tBC = (T/4) + tBC
where T = time period of oscillation of spring mass system
tBC can be obtained from,
BC = AB sin(2π/T)tBC
Putting
we obtain tBC = 
⇒ tAC =
Create a free account to view solution
View Solution FreeMore SHM Questions
A spring of force constant a has two blocks of same mass M connected to each end of the spring as shown in figure. Same ...The total energy of a harmonic oscillator of mass 2kg is 9 joules. If its energy at rest is 5 joules, its K.E. at the me...The phase of a particle in S.H.M. is π/2, then :...Vertical displacement of a plank with a body of mass ′m′ on it is verifying according to law y = sin ωt...A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration a, ...