Work, Power and EnergyHard
Question
A ball is thrown from 10 m height vertically at speed v0 vertically down ward. In colliding surface of earth it looses 50% of its energy and again reach upto same height value of v0 is :-
Options
A.14 m/s
B.9.8 m/s
C.4.9 m/s
D.19.6 m/s
Solution
At it looses 50% of its energy during collision so
K2 =
K1
mv22 = 
v22 =
+ ghAfter collision it is able to reach at 10m height
so
mv22 = mgh
= mgh
+ gh = 2gh
= ghv0 =
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