Work, Power and EnergyHard

Question

A ball is thrown from 10 m height vertically at speed v0 vertically down ward. In colliding surface of earth it looses 50% of its energy and again reach upto same height value of v0 is :-

Options

A.14 m/s
B.9.8 m/s
C.4.9 m/s
D.19.6 m/s

Solution

       
At it looses 50% of its energy during collision so
K2 = K1
mv22 =
v22 = + gh
After collision it is able to reach at 10m height
so mv22 = mgh
= mgh
+ gh = 2gh
= gh
v0 =

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