ThermodynamicsHard
Question
An ideal gas is taken through a process where dQ = dU - dW. The specific heat of the ideal gas in this process is (dQ = heat supplied to the gas, dU = change in internal energy, dW = work done by gas)
Options
A.Cv
B.Cv + 
R
RC.Cv - R
D.the process is impossible
Solution
dQ = dU - dW, again dQ = dU + dW
⇒ dW = pdV = 0
⇒ dW = pdV = 0
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
If the temperature of a body is 140oF, its value in oC will be :-...The correct value of 0oC on kelvin scale is :...In an adiabatic process the quantity which remains constant is :...An ideal gas at 27oC is compressed adiabatically to 8/27 of its original volume. If γ = 5/3, then the rise in tempe...The above p-v diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The amoun...