Photoelectric EffectHard

Question

In the experiment of P.E.E., if incident wavelength of light is λ then kmax of photo electrons is l ev. If λ is replaced by λ/2 then kmax is 3eV. What will be value of kmax if wavelength of light is 2λ :-

Options

A.0.5 eV
B.0.25 eV
C.0.75 eV
D.Zero

Solution

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